3-5/y-2/y^2=0

Solution for 3-5/y-2/y^2=0 equation:

D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

3-(5/y)-(2/(y^2)) = 0

3-5*y^-1-2*y^-2 = 0

t_1 = y^-1

3-2*t_1^2-5*t_1^1 = 0

3-2*t_1^2-5*t_1 = 0

DELTA = (-5)^2-(-2*3*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+5)/(-2*2) or t_1 = (5-49^(1/2))/(-2*2)

t_1 = -3 or t_1 = 1/2

t_1 = -3

y^-1+3 = 0

1*y^-1 = -3 // : 1

y^-1 = -3

-1 < 0

1/(y^1) = -3 // * y^1

1 = -3*y^1 // : -3

-1/3 = y^1

y = -1/3

t_1 = 1/2

y^-1-1/2 = 0

1*y^-1 = 1/2 // : 1

y^-1 = 1/2

-1 < 0

1/(y^1) = 1/2 // * y^1

1 = 1/2*y^1 // : 1/2

2 = y^1

y = 2

y in { -1/3, 2 }